Treffer: Representation of odd integers as the sum of one prime, two squares of primes and powers of 2: Representation of odd integers as the sum of one prime, two squares of primes and powers of~2
Title:
Representation of odd integers as the sum of one prime, two squares of primes and powers of 2: Representation of odd integers as the sum of one prime, two squares of primes and powers of~2
Authors:
Source:
Acta Arithmetica. 115:97-118
Publisher Information:
Institute of Mathematics, Polish Academy of Sciences, 2004.
Publication Year:
2004
Subject Terms:
Document Type:
Fachzeitschrift
Article
File Description:
application/xml
Language:
English
ISSN:
1730-6264
0065-1036
0065-1036
DOI:
10.4064/aa115-2-1
Access URL:
https://www.impan.pl/shop/publication/transaction/download/product/82541?download.pdf
https://zbmath.org/2120192
https://doi.org/10.4064/aa115-2-1
http://yadda.icm.edu.pl/yadda/element/bwmeta1.element.bwnjournal-article-doi-10_4064-aa115-2-1
https://www.impan.pl/pl/wydawnictwa/czasopisma-i-serie-wydawnicze/acta-arithmetica/all/115/2/82541/representation-of-odd-integers-as-the-sum-of-one-prime-two-squares-of-primes-and-powers-of-2
http://journals.impan.pl/cgi-bin/doi?aa115-2-1
https://zbmath.org/2120192
https://doi.org/10.4064/aa115-2-1
http://yadda.icm.edu.pl/yadda/element/bwmeta1.element.bwnjournal-article-doi-10_4064-aa115-2-1
https://www.impan.pl/pl/wydawnictwa/czasopisma-i-serie-wydawnicze/acta-arithmetica/all/115/2/82541/representation-of-odd-integers-as-the-sum-of-one-prime-two-squares-of-primes-and-powers-of-2
http://journals.impan.pl/cgi-bin/doi?aa115-2-1
Accession Number:
edsair.doi.dedup.....ef3e8afb5a2343c7a6a389e7d7c0e4a5
Database:
OpenAIRE
Weitere Informationen
The author addresses the problem of giving a lower bound for the number of powers of two needed to write every large odd integer as \[ N= p_1 + p_2^2 + p_3^2 + 2^{v_1}+ \cdots + 2^{v_k}. \] where \(p_1, p_2, p_3\) are prime numbers. Denoting by \(r_k(N)\) the number of solutions of the equation above, the author proves the following: There exists a constant \(k_0\geq 22000\) and a constant \(N_k\) depending only on \(k\) such that if \(N\geq N_0\), \(k\geq k_0\), then \(r_k(N)>0\). The main technique used on the proof is the circle method.